Hostname: page-component-cd9895bd7-jkksz Total loading time: 0 Render date: 2024-12-25T02:20:19.247Z Has data issue: false hasContentIssue false

On product sets in a unimodular group

Published online by Cambridge University Press:  24 October 2008

M. McCrudden
Affiliation:
University of Birmingham

Extract

It has been pointed out to me by Professor A. M. Macbeath that the proof of Theorem 2 which is given in (2) is incorrect, in that it relies on Proposition 3·1 of (2), which is false, the mistake in its proof being the assumption that in an arbitrary compact topological space, every sequence has a convergent subsequence. However, we can still prove Theorem 2 of (2), simply by replacing section 3 of (2) by the corrected section 3 below, and replacing the proof of Proposition 4·2 of (2) by the corrected proof of Proposition 4·2 given below.

Type
Correction
Copyright
Copyright © Cambridge Philosophical Society 1970

Access options

Get access to the full version of this content by using one of the access options below. (Log in options will check for institutional or personal access. Content may require purchase if you do not have access.)

References

REFERENCES

(1)Halmos, P.Measure theory (New York, 1950).CrossRefGoogle Scholar
(2)McCrudden, M.On product sets in a unimodular group. Proc. Cambridge. Philos. Soc. 64 (1968), 10011007.CrossRefGoogle Scholar
(3)Saks, S.Theory of the integral (Warsaw, 1937: 2nd edition).Google Scholar