Summary
Definition. A group of automorphisms of a group P stabilizes a chain if. Here [a, x] = x−ax for x ∈ P, a ∈ A.
Theorem 0.1. If a group of automorphisms A of a π'-group P stabilizes a chain, then A is a π-group.
Proof. Suppose a ∈ A is a π-automorphism of P. Clearly, by induction we may assume that [a, P1] = 1. Then if x ∈ P, xa = xy where y ∈ P1, since.
It follows that.
Since y is a π- element while a is a π'-element, we have that y = 1 and [a, P] = 1. Thus a = 1 and A is a π-group.
Corollary 0. 2. If A is a π'-group of automorphisms of a π-group P such that [P, A, A] = 1, then [P, A] = 1 and so A = 1.
Proof. A stabilizes the chain.
Lemma 0. 3. Let A be a π-group of automorphisms of a π-group P. Let Q be an A-invariant normal subgroup of P. Then CP/Q(A) = CP(A)Q/Q.
Proof. Clearly.
Suppose now that xQ is a coset of Q in P which is fixed by A. Let QA act as a group of permutations on xQ where A acts in the obvious way and Q acts by multiplication on the right.
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- Topics in Finite Groups , pp. 1 - 79Publisher: Cambridge University PressPrint publication year: 1976