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Corrigenda to Satorra, A., and Bentler, P.M. (2010), “Ensuring Positiveness of the Scaled Difference Chi-Square Test Statistic,” Psychometrika, 75, pp. 243–248

Published online by Cambridge University Press:  11 February 2025

Albert Satorra*
Affiliation:
Universitat Pompeu Fabra, Barcelona
Peter M. Bentler
Affiliation:
University of California, Los Angeles
*
Corresponding author: Albert Satorra; Email: [email protected]
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Abstract

Type
Corrigendum
Creative Commons
Creative Common License - CCCreative Common License - BY
This is an Open Access article, distributed under the terms of the Creative Commons Attribution licence (https://creativecommons.org/licenses/by/4.0), which permits unrestricted re-use, distribution and reproduction, provided the original article is properly cited.
Copyright
© The Author(s), 2025. Published by Cambridge University Press on behalf of Psychometric Society

On page 245, lines 3 and 4, of the published paper, we find the following text:

“Since $\mbox {tr}\, \{U_d \Gamma \} $ can be expressed as the trace of the product of two positive definite matrices, $\mbox {tr}\, \{U_d \Gamma \}>0$ , and thus $c_d>0$ ;”

This text should be replaced with:

“Since $ \mbox {tr}\, \{ U_d \Gamma \} $ can be expressed as the trace of a positive definite matrix, $\mbox {tr}\, \{U_d \Gamma \}>0$ , and thus $c_d>0$ ;”

The uncorrected text claims that $U_d$ and $\Gamma $ are positive definite matrices, but $U_d$ can’t be positive definite, since its rank (difference between the ranks of the derivatives of the two models involved) is much less than its order.

The expression $\mbox {tr}\, \{ U_d \Gamma \} $ could be written differently so that the conclusion still holds. Namely, write $U_d = V \Pi P^{-1} A^\prime (A P^{-1} A^\prime )^{-1} A P^{-1} \Pi ^\prime V $ (formula (4) of the paper) as $U_d = FF^\prime $ , where ${F =V \Pi P^{-1} A^\prime (A P^{-1} A^\prime )^{-1/2}}$ ; then, $\mbox {tr}\, \{ U_d \Gamma \} = \mbox {tr}\, \{ FF^\prime \Gamma \} = \mbox {tr}\, \{ F^\prime \Gamma F \},$ where $F^\prime \Gamma F$ is a positive definite matrix, given that $\Gamma $ is positive definite in the setup of the paper.

For rewriting the alternative expression of $\mbox {tr}\, \{ U_d \Gamma \}$ , we used the well-known matrix algebra result that $\mbox {tr}\, \{M N \} =\mbox {tr}\, \{N M \} $ for matrices M and N of dimensions conformable with the products; in our application, $M= F$ and $N=F^{\prime } \Gamma $ .