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1/1.2 + 1/2.3 + 1/3.4 + … + 1/n(n + 1) = n/n + 1

Published online by Cambridge University Press:  22 September 2016

A. Gardiner*
Affiliation:
Mathematics Department, University of Birmingham, B15 2TT

Abstract

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Type
Notes
Copyright
Copyright © Mathematical Association 1983 

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