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The nutritive value of grasses grown in Uganda when fed to zebu cattle II. The relation between crude fibre and nitrogen-free extract and other nutrients

Published online by Cambridge University Press:  27 March 2009

R. M. Bredon
Affiliation:
Animal Health Research Centre, Entebbe, Uganda
K. W. Harker
Affiliation:
Animal Health Research Centre, Entebbe, Uganda
B. Marshall
Affiliation:
Animal Health Research Centre, Entebbe, Uganda

Extract

The correlation between chemical composition and nutritive value of grass fed to short-horn zebu steers in Uganda was investigated. The following regression equations were calculated from the experimental results and discussed in part I of this paper.

Dig. coef. of C.P. = 100·89 log c.p. – 44·45;

r = 0·9738, P < 0·001.

(For use when fodders of wide range of proteins are compared.)

Dig. coef. of c.p.= 5·14 c.p.;

r – 0·9339, P < 0·001.

(For quick calculation when only approximate figures are required.)

Dig. coef. of c.p. = 9·588 + 4·284 c.p.;

r = 0·9521, P < 0·001.

To be used between 4·5 and 17% of crude protein.)

% c.p. in grass eaten = 1·677 c.p.in

faeces – 6·93; r = 0·958, P < 0·001.

Dig. coef. of d.m. = 41·81 + 1·63 c.p.;

r = 0·9362, P < 0·001.

Dig. coef. of o.m.= 46·05 + 1·4152 c.p.;

r = 0·8851, P < 0·001.

The regression equations calculated from the experimental results in the present paper (part II) are as follows:

Dig. coef. of d.m. = 150·88 – 1·179 (c.f. + n.f.e.);

r = 0·9634, P < 0·001.

Dig. coef. of d.m. = 120·03 – 1·778 c.f.;

r = 0·721, P < 0·01.

Dig. coef. of o.m. = 142·50 – 1·045 (c.f. + n.f.e.);

r = 0·9320, P < 0·001.

t.d.n.= 129·39 – 0·9419 (c.f. + n.f.e.);

r = 0·9288, P < 0·001.

t.d.n. = 7·76 + 0·8192 dig. coef. of d.m.;

r = 0·9886, P < 0·001.

s.e. = 0·9367 dig. coef. of d.m. – 20·15;

r = 0·9832, P < 0·001.

s.e. = 120·80 – 1·104 (c.f. + n.f.e.);

r = 0·9468, P < 0·001.

s.e. = 99·44 – 1·868 c.f.

r = 0·7948, P < 0·01.

Type
Research Article
Copyright
Copyright © Cambridge University Press 1963

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References

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